What is the vertex of the quadratic function f (x) = (X-8) (x-2)

(5, - 9)

Step-by-step explanation:

This function has two zeros, which are {2, 8}. The x-coordinate of the vertex is midway from 2 to 8, or 5.

The y-coordinate is found by substituting 5 for x in f (x) = (X-8) (x-2):

f (5) = (5 - 8) (5 - 2) = - 9

Thus, the vertex is at (5, - 9).