Can 12 (x^3+y^2) + 6 (y^2+1) be the factored form of 12x^3+18y^2+6?

Question

Dante Rosario

Mathematics

20 July, 13:19

Can 12 (x^3+y^2) + 6 (y^2+1) be the factored form of 12x^3+18y^2+6?

+1

Answers (2)

Know the Answer?

Hershey · Answer 1

The correct answer is yes. just distribute 12 to all within first set then 6 to all in 2nd set then add like terms

Jovani Randall · Answer 2

YES

Step-by-step explanation:

So how you can figure this out is you do the Distributive Property.

So it will be 12x^3+12y^2+6y^2+6.

The next thing you have to do is add together the ones that are similar which is 12y^2+6y^2 to get 18y^2.

Your answer is 12x^3+18y^2+6. So YES it can be factored into that form.