If 6 components are drawn at random from the container, the probability that at least 4 are not defective is. If 8 components are drawn at random from the container, the probability that exactly 3 of them are defective is

There is some inforrmation that is missing in this question. It should read:

A container holds 50 electronic components, of which 10 are defective. If 6 components are drawn at random from the container, the probability that at least 4 are not defective is. If 8 components are drawn at random from the container, the probability that exactly 3 of them are defective is.

Answers

Part 1. 0.02

Part 2. 0.0375

Explanation

The probability is a chance of an event happening. It is calculated as;

probability = (Number of favourable outcome) / (Number of available outcome)

Part 1

6 are chosen at random. If 4 are not defective, then 2 are defective.

P (at least 4 are not defective) = 4/40 * 2/10

= 1/10 * 1/5

= 1/50

= 0.02

Part 2

8 are chosen at random. If 3 are defective, the 5 are not defective.

P (3 are defective) = 3/40 * 5/10

= 15/400

= 3/80

= 0.0375