Find the area of a sector with a central angle of 32° and a radius of 8.5 millimeters. Round to the nearest tenth.

A. 40.4 mm²

B. 2.4 mm²

C. 20.2 mm²

D. 9.5 mm²

360 degrees in a circle

32/360 of total area is sector area

area=pir^2

r=8.5

area=pi8.5^2

area=226.980022 mm^2

multiply it by 32/360

sector=20.17600195555556

round

sector=20.2

C is answer