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Selina Pena
Mathematics
16 January, 04:29
Zeros of function y=x^2-3x-18
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Adrien
16 January, 04:49
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Substitute 0 for y and then solve for x
0=x^2-3x-18
x^2-3x-18
factor
(x-6) (x+3)
so set each factor equal to 0
x-6=0
x=6
x+3=0
x=-3
so the zeroes are - 3,6
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