Set y = 22x+4 and y = 14x+28 equal and solve algebraically

Question

Journey Conway

Mathematics

29 April, 03:20

Set y = 22x+4 and y = 14x+28 equal and solve algebraically

+3

Answers (1)

Know the Answer?

Ellen Perkins · Answer 1

x = 3; y = 70.

Step-by-step explanation:

When you set the two equations equal to each other you get:

22x + 4 = 14x + 28

This is a multi-step equation since the variable is on both sides of the equal sign. In order to solve any equation, you must use inverse (opposite) operations to isolate the variable and whatever you do to one side of the equal sign, you must do to the other. The first step for this equation is to get the variable on one side and the constants on the other. Subtracting 14x from both sides: 22x - 14x + 4 = 14x - 14x + 28 gives us 8x + 4 = 28. Next, subtract the 4 from both sides to get: 8x + 4 - 4 = 28 - 4 or 8x = 24. Lastly, divide both sides by 8 to get x = 3. To solve for y, simply plug 3 in for 'x' in either of the initial equations: y = (22) (3) + 4 = 70.