The length of a rectangle is twice its width. The perimeter is 60 ft. Find its area. In the form of a paragraph, explain in complete sentences the steps necessary to find the area. Include a diagram of the rectangle, the steps used to solve for the area, and the final answer in your explanation.

Question

Rhett Salazar

Mathematics

15 January, 17:14

The length of a rectangle is twice its width. The perimeter is 60 ft. Find its area. In the form of a paragraph, explain in complete sentences the steps necessary to find the area. Include a diagram of the rectangle, the steps used to solve for the area, and the final answer in your explanation.

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Answers (1)

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Dario Flynn · Answer 1

Set the following: Length = L Width = W

The length is twice the width: L = 2*W or: W = L/2

Perimeter: P = 60ft = 2*L + 2*W

Substituting L for W in the perimeter equation gives:

P = 60ft = 2*L + 2 * (L/2) = 2*L + L = 3L

L = 60ft/3 = 20ft W=L/2=20ft/2=10ft

Verify result: Perimeter = P = 60ft = 2L + 2W = 2*20ft + 2*10ft = 40ft+20ft = 60ft

The area of the rectangular is: Area = A = Length*Width = L*W = 20ft*10ft = 200 (ft) ^2

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