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12 April, 01:32

A machine operation produces bearings whose diameters are normally distributed, with a mean of 0.497 inch and a standard deviation of 0.003 inch. suppose that specifications require that the bearing diameter be 0.500 inch plus or minus 0.004 inch. normal distribution: $/mu = 0.497$, $/sigma = 0.003$. specifications: (0.496, 0.504) what proportion of the production will be unacceptable?

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  1. 12 April, 01:59
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    Mean = 0.497 in, SD = 0.003 in

    Required diameter ranges between 0.496 in and 0.504 in

    Anything other diameter obtained is not acceptable.

    That is;

    P (x0.504) are not acceptable.

    Now,

    P (x<0.496) = P (Z< (0.496-0.497) / 0.003)) = P (Z<-0.33)

    From Z tables, P (Z<-0.33) = 0.3707

    Similarly,

    P (x>0.504) = P (Z> (0.504-0.497) / 0.003)) = P (Z>2.33)

    From Z tables, P (Z>2.33) = 1-0.9901 = 0.0099

    Therefore, unacceptable proportion = P (x0.504) = 0.3707+0.0099 = 0.3806 or 38.06%
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