The equation of the circle whose center is at (2, 1) and radius is 3 is (x + 2) ² + (y + 1) ² = 9 (x - 2) ² + (y - 1) ² = 9 (x - 2) ² + (y - 1) ² = 3
+1
Answers (1)
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “The equation of the circle whose center is at (2, 1) and radius is 3 is (x + 2) ² + (y + 1) ² = 9 (x - 2) ² + (y - 1) ² = 9 (x - 2) ² + (y ...” in 📗 Mathematics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Home » Mathematics » The equation of the circle whose center is at (2, 1) and radius is 3 is (x + 2) ² + (y + 1) ² = 9 (x - 2) ² + (y - 1) ² = 9 (x - 2) ² + (y - 1) ² = 3