Factor the polynomial completely.

2x^3+16x^2+7x+56

A. (x^2+8) (x+7)

B. (2x^2+7) (x+8)

C. (x^2+7) (x+8)

D. (2x^2+8) (x+7)

Question

Mireya

Mathematics

20 December, 22:49

Factor the polynomial completely.

2x^3+16x^2+7x+56

A. (x^2+8) (x+7)

B. (2x^2+7) (x+8)

C. (x^2+7) (x+8)

D. (2x^2+8) (x+7)

+2

Answers (2)

Know the Answer?

Julissa Davies · Answer 1

Julissa Davies 20 December, 23:06

0

B. The answer is letter B.

Elisha · Answer 2

We can simplify this by separating this into 2 sections. 2x^3 + 16x^2 and 7x+56. The GCF of 2x^3 + 16x^2 is 2x^2 and the GCF of 7x+56 is 7. When we factor out these numbers we are left with (x+8) for both. The simplified equation is (2x^2 + 7) (x+8)

Factor the polynomial completely.2x^3+16x^2+7x+56A. (x^2+8) (x+7)B. (2x^2+7) (x+8)C. (x^2+7) (x+8)D. (2x^2+8) (x+7)

Factor the polynomial completely.

2x^3+16x^2+7x+56

A. (x^2+8) (x+7)

B. (2x^2+7) (x+8)

C. (x^2+7) (x+8)

D. (2x^2+8) (x+7)