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30 December, 04:42

Three consecutive odd intergers have a sum of 27. find the integers

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  1. 30 December, 05:05
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    Solve for x:

    x + (x + 2) + (x + 4) = 27

    3x + 6 = 27

    3x = 27 - 6

    3x = 21

    3x / 3 = 21 / 3

    x = 7

    The integers:

    x + (x + 2) + (x + 4) = 27

    7 + (7 + 2) + (7 + 4) = 27

    7 + 9 + 11 = 27

    27 = 27

    The integers are 7, 9, 11
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