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6 February, 05:13

Speed of Plane A = 450 mph.

Speed of Plane B = 350 mph.

Both planes leave from Kansas City at the same time.

Plane A flies due West.

Plane B flies due South.

After 2.5 hours, how far is Plane A from Plane B?

A. 1,425.0

B. 1,322.0

C. 1,258.5

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Answers (1)
  1. 6 February, 05:27
    0
    The answer would be A:

    You would use distance=rate•time to solve:

    450 • 2.5 = 1125

    350• 2.5 = 875

    Since plane A is going west and B is going south, they form a right triangle, so you can use the Pythagorean theorem to solve for the distance between them, which we will represent as x:

    1125² + 875² = x²

    1265625 + 765265 = x²

    2030890 = x²

    Once you square root x, it's about 1425.09298, which is closest to answer A, 1425.0
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