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Solve the compound inequality 8x > - 32 or 6x ≤ - 48.

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  1. 23 July, 21:59
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    On the 8x > - 32 first divide by the 8 from the both sides.

    8x/8 as a fractions and it is greater than negative 32/8 as a fraction. And the equals to x is greater than negative 4.

    On the 6x ≤ - 48. Then divide by 6 from the both sides.

    6x/6 as a fractions and it is less than negative 48/6 as a fraction. And the equals to x≤ negative 8.
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