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What is the value of the discriminant?

2K2 = 10k - 2

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  1. 21 May, 21:36
    0
    84

    Step-by-step explanation:

    Given a quadratic equation in standard form, ax² + bx + c = 0 : a ≠ 0

    Then the discriminant is Δ = b² - 4ac

    2k² = 10k - 2 (subtract 10k - 2 from both sides)

    2k² - 10k + 2 = 0 ← in standard form

    with a = 2, b = - 10 and c = 2, thus

    b² - 4ac = ( - 10) ² - (4 * 2 * 2) = 100 - 16 = 84
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