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20 August, 06:29

The length of a rectangle is five times its width. if the area of the rectangle is 405 yd2, find its perimeter.

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  1. 20 August, 06:41
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    L = 5W

    A = LW = 405

    plug in 5W FOR L

    A = LW

    A = (5W) W = 405

    5W^2 = 405

    W^2 = 405/5

    W^2 = 81

    Take the squareroot

    w = 9

    L = 5W

    We now know W = 9

    L=5 (9)

    L = 45

    P=2 (L+W)

    P = 2 (45 + 9)

    P = 108
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