What is the solution to this system of equations?

Y=2x-2

8x+2y=-16

The first equation defines y for us, so all we have to do is substitute 2x - 2 into the 2nd equation for y and solve.

8x + 2 (2x - 2) = - 16

8x + 4x - 4 = - 16

12x - 4 = - 16

12x = - 12

x = - 1

Now that we have a value for x, we substitute - 1 back into one of the equations to find the y value.

y = 2x - 2

y = 2 (-1) - 2

y = - 2 - 2

y = - 4

So our solution set is

(-1, - 4)