Given a triangle with b = 10, c = 11, and A = 43°, what is the length of a? Round to the nearest tenth.

7.2

8.8

7.8

8.4

Length of side a is 7.8

Option C is correct

Step-by-step explanation:

Given b=10, c=11 and A = 43°, we need to find the length of a.

Using the Law of Cosines

a^2 = b^2+c^2-2bccosA

a^2 = (10) ^2 + (11) ^2-2 (10) (11) (cos 43°)

a^2 = 100+121-2 (110) (0.7313)

a^2=100+121-160.886

a^2=221-160.886

a^2=60.114

a=√60.114

a = 7.75

a≈ 7.8

So, length of side a is 7.8

Option C is correct