Andre hit a golf ball from the ground and its movement follows the equation hbracket (t) = -16sup (t, 2) + 44t, where t is the time in seconds, and hbracket (t) is the height of the ball at a given time t. Find the time that it took the golf ball to hit the ground again correct to two decimal places.

Question

Friedman

Mathematics

14 October, 00:42

Andre hit a golf ball from the ground and its movement follows the equation hbracket (t) = -16sup (t, 2) + 44t, where t is the time in seconds, and hbracket (t) is the height of the ball at a given time t. Find the time that it took the golf ball to hit the ground again correct to two decimal places.

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Answers (1)

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Armando Landry · Answer 1

Answer: the golf ball with hit the ground again after 2.75 seconds

Step-by-step explanation:

The movement of the golf ball from the ground follows the equation h (t) = -16t^2+44t,

where t is the time in seconds, and h (t) is the height of the ball at a given time t

By the time the golf ball hit the ground, the height from the ground would be zero. This means that we would equate the quadratic equation to zero. It becomes

-16t^2+44t = 0

Dividing both sides by t

16t^2/t = 44t/t

16t = 44

t = 44/16

t = 2.75