Justin, Cam, and Ben are playing a board game where exactly one player will win. Ben estimates that Justin has a 20/%20%20, percent chance of winning each game, and that Cam has a 50/%50%50, percent chance of winning each game.

If Justin, Cam, and Ben were to play the board game 200200200 times, which of the following is the best prediction for the number of times that Ben would win the board game?

Choose 1 answer:

Choose 1 answer:

A

303030

B

454545

C

606060

D

757

Question

Guest

Mathematics

19 April, 07:11

Justin, Cam, and Ben are playing a board game where exactly one player will win. Ben estimates that Justin has a 20/%20%20, percent chance of winning each game, and that Cam has a 50/%50%50, percent chance of winning each game.

If Justin, Cam, and Ben were to play the board game 200200200 times, which of the following is the best prediction for the number of times that Ben would win the board game?

Choose 1 answer:

Choose 1 answer:

A

303030

B

454545

C

606060

D

757

+3

Answers (2)

Know the Answer?

Huerta · Answer 1

To find the change that Ben has of winning out of 200 chances, you will find out what percent chance he has using the percents of the other 2 players.

100% - 50% (Cam) - 20% (Justin) = 30% for Ben

30% of the 200 attempts would be calculated as:

0.30 x 200 = 60.

You should expect Ben to win 60 times, choice C.

Abbott · Answer 2

The best prediction for Ben would be 60 wins out of 200.

If Justin wins 20% of the time and Cam wins 50% of the time, that leaves 30% of the wins for Ben.

To find his predicted amount out of 200, just multiply it by 30%.

0.3 x 200 = 60 wins