A ball is thrown straight up with a initial velocity of 56 feet per second. The height, h, of the ball t seconds after it is thrown is given by the formula h (t) = 56t-16t^2. What is the maximum height of the ball?
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Home » Mathematics » A ball is thrown straight up with a initial velocity of 56 feet per second. The height, h, of the ball t seconds after it is thrown is given by the formula h (t) = 56t-16t^2. What is the maximum height of the ball?