In a competition between players x and y, the first player to win three games in a row or a total of four games wins. how many ways can the competition be played if x wins the first game and y wins the second and third games?

Question

Zaiden Kidd

Mathematics

24 March, 00:42

In a competition between players x and y, the first player to win three games in a row or a total of four games wins. how many ways can the competition be played if x wins the first game and y wins the second and third games?

+5

Answers (1)

Know the Answer?

Skippy · Answer 1

7 ways (y wins 4 of them)

Step-by-step explanation:

Possibilities are ...

{x, y, y, y} - y wins

{x, y, y, x, x, x} - x wins

{x, y, y, x, y, y} - y wins

{x, y, y, x, x, y, x} - x wins

{x, y, y, x, x, y, y} - y wins

{x, y, y, x, y, x, x} - x wins

{x, y, y, x, y, x, y} - y wins