Peter buys a bag of 21 sweets. In the bag there 13 red sweets, 6 green sweets and 2 yellow sweets Peter likes red sweets and eats 3 of them He then asks his sister to choose one sweet at random from the bag. There are 2 questions to answer. What is the probability that she chooses a red sweet? what is the probability that she chooses an orange sweet?

Question

Andrea

Mathematics

15 August, 07:16

Peter buys a bag of 21 sweets. In the bag there 13 red sweets, 6 green sweets and 2 yellow sweets Peter likes red sweets and eats 3 of them He then asks his sister to choose one sweet at random from the bag. There are 2 questions to answer. What is the probability that she chooses a red sweet? what is the probability that she chooses an orange sweet?

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Answers (2)

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Kaylyn · Answer 1

You have to write this as a fraction look at the total number of sweets and turn it in to a fraction there are 21 sweets so that's the denominator there are 13 red sweets so that's the numerator but he took away three so 10/21 is the probability of picking a red sweet

Donavan Rowland · Answer 2

Probability=number of specific outcomes/total number of outcomes ...

Since Peter eats 3 reds there are only 10 reds and 18 total sweets left, therefore the probability of his sister picking a red randomly is:

10/18=5/9

There are no orange sweets so the probability of picking one is zero.