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Mathematics
14 June, 10:35
Factor completely 8y
^2-33y+25
+2
Answers (
1
)
Allisson Escobar
14 June, 10:53
0
We are given the equation 8y^2 - 33y + 25.
First multiply the first and the last coefficients: 8x25 = 200
Now we need to factorize 200 such that these factors add up to the middle coefficient - 33. By trial and error, we find that
200 = (-8) x (-25)
and
-25 - 8 = - 33
So,
8y^2 - 33y + 25
= 8y^2 - 25y - 8y + 25
= y (8y - 25) - (8y - 25)
= (y-1) (8y - 25)
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