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14 June, 10:35

Factor completely 8y

^2-33y+25

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Answers (1)
  1. 14 June, 10:53
    0
    We are given the equation 8y^2 - 33y + 25.

    First multiply the first and the last coefficients: 8x25 = 200

    Now we need to factorize 200 such that these factors add up to the middle coefficient - 33. By trial and error, we find that

    200 = (-8) x (-25)

    and

    -25 - 8 = - 33

    So,

    8y^2 - 33y + 25

    = 8y^2 - 25y - 8y + 25

    = y (8y - 25) - (8y - 25)

    = (y-1) (8y - 25)
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