4log (2x - 5) + 6 = 14

Step-by-step explanation:

Given that,

4log (2x - 5) + 6 = 14

Subtract 6 from both sides

4log (2x - 5) + 6 - 6 = 14 - 6

4log (2x - 5) = 8

Divide both side by 4

4log (2x - 5) : 4 = 8 : 4

log (2x - 5) = 2

If the base of the Log is 10

Take antilog of both sides

Then, Log (2x-5) = 2, becomes

(2x-5) = 10²

2x-5=100

2x=105

x=105/2

x=52.5