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22 September, 12:14

City A and City B had two different temperatures on a particular day. On that day, four times the temperature of City A was 8° C more than 3 times the temperature of City B. The temperature of City A minus twice the temperature of City B was - 3° C. What was the temperature of City A and City B on that day?

Your answer:

City A was 5° C, and City B was 4° C.

City A was 3° C, and City B was - 1° C.

City A was 8° C, and City B was - 3° C.

City A was 5° C, and City B was - 5° C.

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Answers (1)
  1. 22 September, 12:37
    0
    City A = x

    City B = y

    1st equation: 4x-8 = 3y

    2nd equation: x-2y = - 3, rewrite as x = 2y-3

    replace x in eq. 1 with equation 2

    4 (2y-3) - 8 = 3y

    8y-12-8=3y

    8y-20 = 3y

    -20 = - 5y

    y = - 20/-5 = 4

    x = 2y-3 = 2 (4) - 3 = 5

    City A was 5° C, and City B was 4° C.
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