How do you do,

2^n=88

rounding your answers to the nearest ten-thousandth (using logs)

I forget how to do the equation

2^n = 88

To solve an equation with a variable in the power you have to use logs.

Take the log of both sides.

log 2^n = log 88

Using the power rule of logs, bring the n to the front, it becomes a coefficient.

n * log 2 = log 88

Divide both sides by log 2

n = (log 88) / (log 2)

n = 6.4594