In the video, I drop a ball off a three-story balcony. We know that objects in freefall follow the equation for height h, in meters, h = - 4.9 t 2 + c h = - 4.9 t 2 + c, where t is time in seconds, and c is the initial height. A student timed the drop at 1.48 seconds.

Question

Glenn Key

Mathematics

27 March, 16:29

In the video, I drop a ball off a three-story balcony. We know that objects in freefall follow the equation for height h, in meters, h = - 4.9 t 2 + c h = - 4.9 t 2 + c, where t is time in seconds, and c is the initial height. A student timed the drop at 1.48 seconds.

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Focker · Answer 1

Step-by-step explanation:

The equation is

h (t) = - 4.9t² + c

where h (t) is the height after its fall and c is the height from which it fell. We know that when an object hits the ground, its height is 0. Therefore, h (t) = 0 when the object is on the ground. If we want to solve for the height from which the object fell, we have to sub the time in for t and solve for c when h (t) = 0:

0 = - 4.9 (1.48) ² + c and

0 = - 10.73296 + c so

c = 10.73296 meters