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31 July, 15:34

A rectangle has a length that is 4 units longer than the width. If the width is increased by 7 units and the length increased by 5 units, write an equivalent expression for the area of the rectangle. Group of answer choices

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  1. 31 July, 15:56
    0
    A = (x + 7) (x + 9)

    Step-by-step explanation:

    Let the width w = x

    then length l = w + 4 = x + 4

    Area = length x width

    = x (x+4)

    Then the the width is increased by 7 units and the length increased by 5 units.

    w = x + 7

    l = (x + 4) + 5 = x + 9

    A = (x + 7) (x + 9)
  2. 31 July, 16:02
    0
    Area of rectangle = length * Width

    In this case

    Assuming "w" as the width of rectangle,

    Area = (w + 9) (w + 7)

    Step-by-step explanation:

    Let "w" be the width of rectangle,

    so

    length = w + 4, as it is 4 units greater.

    Width = w

    Now after adding 5 units in length and 7 units in width, now our measurments will be,

    length = w + 4 + 5 = w+9

    width = w+7.

    So now area will be

    A = (w+9) (w+7).
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