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Byrd
Mathematics
15 March, 21:19
Prove
cosA x cos2A x cos4A x cos8A = sin16A/16sinA
+1
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Clinton Weeks
15 March, 21:42
0
Given cosA x cos2A x cos4A x cos8A = sin16A/16sinA
RHS
sin16A/16sinA
[2sin8A cos 8A]/16sinA
[cos8A (2sin4A cos4A) ]/8sinA
[cos8A cos 4A (2 sin 2A cos 2A) ]/4sinA
[cos 8A cos 4A cos 2A (sin2A) ]/2 sinA
[cos8A cos 4A cos 2A (2sinA cos A) ]/2
sin A cos A cos 2A cos 4A cos 8A
Hence RHS=LHS
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