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15 March, 21:19

Prove

cosA x cos2A x cos4A x cos8A = sin16A/16sinA

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Answers (1)
  1. 15 March, 21:42
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    Given cosA x cos2A x cos4A x cos8A = sin16A/16sinA

    RHS

    sin16A/16sinA

    [2sin8A cos 8A]/16sinA

    [cos8A (2sin4A cos4A) ]/8sinA

    [cos8A cos 4A (2 sin 2A cos 2A) ]/4sinA

    [cos 8A cos 4A cos 2A (sin2A) ]/2 sinA

    [cos8A cos 4A cos 2A (2sinA cos A) ]/2

    sin A cos A cos 2A cos 4A cos 8A

    Hence RHS=LHS
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