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F (1) = 16 f (n) = (n-1) + 2n what is f (4)

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  1. 2 May, 02:20
    0
    F (4) = (4-1) + 2*4=11 ...

    This seems a bit too easy though, did you mean f (n) = f (n-1) + 2n? In this case:

    f (1) = 16

    f (2) = 16+2*2=20

    f (3) = 20+2*3=26

    f (4) = 26+2*4=34
  2. 2 May, 02:31
    0
    F (1) = 16

    f (n) = (n - 1) + 2n

    f (4) = 64

    f (4) = (4 - 1) + 2 (4)

    f (4) = 3 + 8

    f (4) = 11
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