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Haleigh Boyle
Mathematics
13 October, 19:49
How to convert (x+6) (x-2) to standard form
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Katie Sanders
13 October, 19:55
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The standard form is ax² + bx + c = 0
To convert it in standard form, multiply it.
(x+6) (x-2)
x² - 2x + 6x - 12
x² + 4x - 12 = 0
Now this is in the standard form where,
a = 1
b = 4
c = - 12
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