Which quadratic equation is equivalent to (x + 2) ^2 + 5 (x + 2) - 6 = 0? A. (u + 2) ^2 + 5 (u + 2) - 6 = 0 where u = (x - 2) B. u^2 + 4 + 5u - 6 = 0 where u = (x - 2) C. u^2 + 5u - 6 = 0 where u = (x + 2) D. u^2 + u - 6 = 0 where u = (x + 2) (This is a question from Edg by the way)

Question

Lyric

Mathematics

16 February, 22:38

Which quadratic equation is equivalent to (x + 2) ^2 + 5 (x + 2) - 6 = 0? A. (u + 2) ^2 + 5 (u + 2) - 6 = 0 where u = (x - 2) B. u^2 + 4 + 5u - 6 = 0 where u = (x - 2) C. u^2 + 5u - 6 = 0 where u = (x + 2) D. u^2 + u - 6 = 0 where u = (x + 2) (This is a question from Edg by the way)

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Answers (2)

Know the Answer?

Kinley · Answer 1

C. u^2+5u-6=0

Step-by-step explanation:

By comparing (x+2) ^2+5 (x+2) - 6=0 to answer C, that is u^2+5u-6=0, u = (x+2).

By sustituting (x+2) into answer C, we get;

(x+2) ^2+5 (x+2) - 6=0 which is the same as the quadriatic equation given in the question.

Rodolfo Conway · Answer 2

C. u^2 + 5u - 6 = 0 where u = (x + 2)

Step-by-step explanation:

(x + 2) ^2 + 5 (x + 2) - 6 = 0

Let u = x+2

(u) ^2 + 5 (u) - 6 = 0