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6 October, 17:40

Susan invests twice as much money at 7.5% as she does at 6%. If her total interest after a year is $840 how much does she have invested at each rate?

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  1. 6 October, 17:44
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    Let x be the amount invested at 6%

    840 = 0.06x + 0.075 (2x)

    840 = 0.06x + 0.15x

    840 = 0.21x

    x = 840/0.21

    x = 4000

    Therefore, she invests $4000 at 6% and $8000 at 7.5%
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