Wayne and Winston collect old coins. Winston has 8 fewer coins than Wayne has. If you add 4 times the number of coins Wayne has and 3 times the number of coins Winston has, the sum is 375.

This system of linear equations relates the number of coins Wayne has (x) and the number of coins Winston has (y)

y=x-8

4x+3y=375

The best method to solve this system of equations is substitution or elimination

Wayne has 41 or 50 or 57 or 59 coins, and Winston has 33 or 42 or 47 or 49 coins

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Mathematics

28 April, 14:05

Wayne and Winston collect old coins. Winston has 8 fewer coins than Wayne has. If you add 4 times the number of coins Wayne has and 3 times the number of coins Winston has, the sum is 375.

This system of linear equations relates the number of coins Wayne has (x) and the number of coins Winston has (y)

y=x-8

4x+3y=375

The best method to solve this system of equations is substitution or elimination

Wayne has 41 or 50 or 57 or 59 coins, and Winston has 33 or 42 or 47 or 49 coins

+2

Answers (1)

Know the Answer?

Cierra Norris · Answer 1

Wayne has 57 coins, and Winston has 49 coins. This is by process of elimination AND substitution. This is the only combination that results in a 5 in the ones column.