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6 August, 03:28

A line has the equation 4x - 13 = 2y. Write an equation of a line parallel to

this given line that has a y-intercept of 1.

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Answers (2)
  1. 6 August, 03:35
    0
    y = 2x + 1

    Step-by-step explanation:

    4x - 13 = 2y

    y = (4x-13) / 2

    y = 2x - 13/2

    The new equation will have the same slope (m = 2), as the lines are parallel

    y = 2x + b

    b represents the y-intercept, so b = 1

    y = 2x + 1
  2. 6 August, 03:51
    0
    y = 2x + 1

    Step-by-step explanation:

    4x - 13 = 2y

    y = (4x-13) / 2

    y = 2x - 13/2

    The new equation will have the same slope (m = 2), as the lines are parallel

    y = 2x + b

    b represents the y-intercept, so b = 1

    y = 2x + 1
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