In right ∆ABC, C is a right angle and sin A = 243/312. What is m ∠B

If sinA=243/312

A=arcsin (243/312) and since B is complementary we can say:

B=90-A

B=90-arcsin (243/312)

B≈38.84° (to nearest one-hundredth of a degree)

Get value of 'A' from a sin table and C is already given 90, hence B can be calculated using angle sum property of a triangle.

alternately, using pythagorus th., find the third side of triangle and then you will know sinB.

again from sin table, get B

sinA = 243/312 = 0.7788

A = 51.16 degrees

B = 180 - 90 - 51.16 = 38.64 degrees (fourth choice)