What are the center and radius of the circle defined by the equation x2 + y2 - 6x + 4y + 4 = 0 A. Center (3, - 2); radius 9 B. Center (-3, 2) radius 9 C. Center (3, - 2); radius 3 D. Center (-3, 2); radius 3

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Mathematics

8 August, 15:17

What are the center and radius of the circle defined by the equation x2 + y2 - 6x + 4y + 4 = 0 A. Center (3, - 2); radius 9 B. Center (-3, 2) radius 9 C. Center (3, - 2); radius 3 D. Center (-3, 2); radius 3

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Makayla Molina · Answer 1

C. Center: (3, - 2); radius: 3

Step-by-step explanation:

x^2 + y^2 - 6x + 4y + 4 = 0

We need to complete the square in x and y.

x^2 - 6x + y^2 + 4y = - 4

x^2 - 6x + 9 + y^2 + 4y + 4 = - 4 + 9 + 4

(x - 3) ^2 + (y + 2) ^2 = 9

Center: (3, - 2); radius: 3