Suppose you are flying a kite that is 50 feet long. While flying, there is a constant gust of wind that blows the kite to an angle of 60° with the ground. How high, in feet, is the kite above the ground

The kite forms a right angled triangle with hypotenuse of 50 ft. The height of the kite above the ground is the opposite of 60° angle.

Using the sine rule,

Sin 60 = Height of the kite above the ground/Hypotenuse

Therefore,

Height of the kite above the ground = Hypotenuse*Sin 60 = 50 * Sin 60 = 43.3 ft