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26 February, 05:13

Suppose you are flying a kite that is 50 feet long. While flying, there is a constant gust of wind that blows the kite to an angle of 60° with the ground. How high, in feet, is the kite above the ground

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  1. 26 February, 05:21
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    The kite forms a right angled triangle with hypotenuse of 50 ft. The height of the kite above the ground is the opposite of 60° angle.

    Using the sine rule,

    Sin 60 = Height of the kite above the ground/Hypotenuse

    Therefore,

    Height of the kite above the ground = Hypotenuse*Sin 60 = 50 * Sin 60 = 43.3 ft
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