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28 December, 12:27

What is the diameter of the smallest circle that would enclose 2,000 pennies?

Recall your model's equation: y=1.11x^{2}

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Answers (1)
  1. 28 December, 12:30
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    Answer: 84.9

    Step-by-step explanation:

    Model's equation: y=1.11x^2

    Since y = 2000

    y = 1.11x^2

    2000 = 1.11x^2

    x^2 = 2000/1.11

    x^2 = 1801.8

    x = 42.45

    Diameter of the smallest circle will be:

    = 2x

    = 2 * 42.45

    = 84.9
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