A circle has the equation x^2-8y-6x+y^2=4.

A: What value should be added to each side of the equation to complete the square for the x's?

B: What value should be added to each side of the equation to complete the square for the y's?

C: What is the standard form of the equation?

Select three answer choices: one for question A, one for question B, and one for question C.

A: 3

B: 4

C: (x-3) 2 + (y-4) 2=29

A: 36

B: 16

C: (x-3) 2 + (y-4) 2=16

A: 9

C: (x-3) 2 + (y-4) 2=25

B: 64

Question

Giovanny Suarez

Mathematics

2 January, 07:00

A circle has the equation x^2-8y-6x+y^2=4.

A: What value should be added to each side of the equation to complete the square for the x's?

B: What value should be added to each side of the equation to complete the square for the y's?

C: What is the standard form of the equation?

Select three answer choices: one for question A, one for question B, and one for question C.

A: 3

B: 4

C: (x-3) 2 + (y-4) 2=29

A: 36

B: 16

C: (x-3) 2 + (y-4) 2=16

A: 9

C: (x-3) 2 + (y-4) 2=25

B: 64

+5

Answers (1)

Know the Answer?

Rockette · Answer 1

Hello here is a solution:

x²-8y-6x+y²=4 ... (1)

A)

x²-6x = x²-2 (3) x+9-9

= x²-2 (3) x+3²-9

x²-6x = (x-3) ² - 9

B)

y²-8y = y²-2 (4) y + 4²-16

y²-8y = (y-4) ²-16

C)

in (1):

(x-3) ² - 9 + (y-4) ²-16 = 4

(x-3) ² + (y-4) ² = 29 ... is the standard form of the equation

Select answer 1:

A: 3

B: 4

C: (x-3) 2 + (y-4) 2=29