On a coordinate plane, 2 exponential functions are shown. Function f (x) approaches y = 0 in quadrant 2 and increases into quadrant 1. It crosses the y-axis at (0, 0.5) and goes through (1, 4). Function g (x) approaches y = 0 in quadrant 3 and decreases into quadrant 4. It crosses the y-axis at (0, negative 0.5) and goes through (1, negative 4).

Which function represents g (x), a reflection of f (x) = Two-fifths (10) x across the x-axis?

g (x) = Negative two-fifths (10) x

g (x) = Negative two-fifths (one-tenth) Superscript x

g (x) = Two-fifths (one-tenth) Superscript negative x

g (x) = Two-fifths (10) - x

Question

Cristal Maynard

Mathematics

17 April, 00:21

On a coordinate plane, 2 exponential functions are shown. Function f (x) approaches y = 0 in quadrant 2 and increases into quadrant 1. It crosses the y-axis at (0, 0.5) and goes through (1, 4). Function g (x) approaches y = 0 in quadrant 3 and decreases into quadrant 4. It crosses the y-axis at (0, negative 0.5) and goes through (1, negative 4).

Which function represents g (x), a reflection of f (x) = Two-fifths (10) x across the x-axis?

g (x) = Negative two-fifths (10) x

g (x) = Negative two-fifths (one-tenth) Superscript x

g (x) = Two-fifths (one-tenth) Superscript negative x

g (x) = Two-fifths (10) - x

+3

Answers (1)

Know the Answer?

Justice Maxwell · Answer 1

g (x) = Negative two-fifths (10) x

Step-by-step explanation:

In order to reflect a function over the x-axis, you have to multiply the function by minus one.

Given the function:

f (x) = 2/5 (10) ^x

Its reflection over the x-axis is:

-f (x) = - 2/5 (10) ^x = g (x)