Find the number and type of solutions for x² + 3x = 10.

a. The equation has two real solutions.

b. Cannot determine without graphing.

The equation has one real solution.

d. The equation has two nonreal complex solutions.

Answer:$A$

Step-by-step explanation:

Lets subtract 10 on both sides. Hence, our equation is x^2+3x-10=0. Applying the quadratic formula, we get our roots as (-3 + / - sqrt (49)) / 2, so the equations roots are (-3 + / -7) / 2 which is obviously real. Hence, our answer is A.