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Julien Willis
Mathematics
5 March, 03:54
What are the x intercepts of x^2-6x+5
+5
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Reese Russo
5 March, 04:17
0
Y = x² - 6x + 5
0 = x² - 6x + 5
x = - (-6) + / - √ ((-6) ² - 4 (1) (5))
2 (1)
x = 6 + / - √ (36 - 20)
2
x = 6 + / - √ (16)
2
x = 6 + / - 4
2
x = 3 + 2
x = 3 + 2 x = 3 - 2
x = 5 x = 1
y = x² - 6x + 5
y = (5) ² - 6 (5) + 5
y = 25 - 30 + 5
y = - 5 + 5
y = 0
(x, y) = (5, 0)
or
y = x² - 6x + 5
y = (1) ² - 6 (1) + 5
y = 1 - 6 + 5
y = - 5 + 5
y = 0
(x, y) = (1, 0)
The x-intercept of the problem is equal to 5 or 1.
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