THE vertices of ABC are A (-2,2, B (6,2, and c (0,8). The perimeter of ABC is

Question

Ariel

Mathematics

1 July, 06:09

THE vertices of ABC are A (-2,2, B (6,2, and c (0,8). The perimeter of ABC is

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Answers (1)

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Jasmine Mooney · Answer 1

Using the distance formula:

AB^2 = (-2-6) ^2 = (2-2) ^2

= 64

AB = 8 units

BC^2 = (6-0) ^2 + (2-8) ^2

= 36 + 36

= 72

BC = 6 root 2

AC^2 = (-2-0) ^2 + (2-8) ^2

= 4 + 36

= 40

AC = 2 root 10

Perimeter = 8 + 6 root 2 + 2 root 10

= 2 (4 + 3 root 2 + root 10) units