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9 December, 08:14

Find the second derivative of xy + y^2 = 1.

The first derivative is - y (x + 2y) ^ (-1).

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  1. 9 December, 08:24
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    Dx (xy + y^2 = 1)

    Dx (xy) + Dx (y^2) = Dx (1)

    (x'y + xy') + (2y y') = (0)

    x'y + y' (x + 2y) = 0

    y' (x + 2y) = - x'y

    y' = - x'y / (x + 2y)
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