The perimeter of a rectangle is 48 cm. The length is 6 cm less than twice the width. Which system would model this situation, and what are the length and the width?

Question

Zackery Sharp

Mathematics

28 October, 23:32

The perimeter of a rectangle is 48 cm. The length is 6 cm less than twice the width. Which system would model this situation, and what are the length and the width?

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Answers (1)

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Paulina Elliott · Answer 1

P = 2 (L + W) or P 2 (L) + 2 (W)

P = 48

L = 2W - 6

48 = 2 (2W - 6 + W)

48 = 2 (3W - 6)

48 = 6W - 12

48 + 12 = 6W

60 = 6W

60/6 = W

10 = W

L = 2W - 6

L = 2 (10) - 6

L = 20 - 6

L = 14

so the width (W) = 10 and the length (L) = 14