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12 April, 06:26

4x-3y+6z=18,-x+5y+4z=48,6x-2y+5z=0 what are x, y, and z?

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  1. 12 April, 06:29
    0
    -1x+5y+4z=48

    4x-3y+6z=18

    6x-2y+5z=0

    multiply the first equation by 4 and add the results to the second equation:

    -1x+5y+4z=48

    17y+22z=210

    6x-2y+5z=0

    multiply the first equation by 6 and add the results to the third equation:

    -1x+5y+4z=48

    17y+22z=210

    28y+29z=288

    multiply the second equation by - 28/17 and add the result to the third equation:

    -1x+5y+4z=48

    17y+22z=210

    -123/17z=-984/17

    solve for z

    -123/17z=-984/17

    z=8

    then solve for y

    17y+22z=210

    17y+22*8=210

    y=2

    solve for x substituting y=2 and z=8 into the first equation:

    4x-3 (2) + 6 (8) = 18

    x=-6

    so the solutions are x=-6, y=2, z=8
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