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25 April, 09:38

Givin sin0 = 12/13, find sec (0)

A. Sec (0) = 13/12

B. Sec (0) = 5/13

C. Sec (0) = 5/12

D. Sec (0) = 13/5

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  1. 25 April, 09:53
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    D. sec (a) = 13/5

    Step-by-step explanation:

    if sin (a) = 12/13, then cos (a) = 5/13, because of 5-12-13 triangles

    sec (a) = 1/cos (a)

    1 / (5/13) = 13/5

    sec (a) = 13/5
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