John took at 5 1/2 mile walk to his friends house. He left at 11am. And arrived at his friend's house at 1pm. What was his average speed of walking? If the return trip took a half hour longer, how much lower was his average speed on return trip that on the trip to his friend's house?

Question

Jakob Holland

Mathematics

12 December, 23:00

John took at 5 1/2 mile walk to his friends house. He left at 11am. And arrived at his friend's house at 1pm. What was his average speed of walking? If the return trip took a half hour longer, how much lower was his average speed on return trip that on the trip to his friend's house?

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Christopher Henry · Answer 1

5.5 miles over 2 hours--> 5.5/2 = 2.75 miles per hour was his average walking speed. 5.5 miles over 2.5 hours - - > 5.5/2.5 = 2.2 miles per hour on the return trip meaning that his average speed was (2.75-2.2 = 0.55) 0.55 miles per hour lower on the return trip