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Robert Peck
Mathematics
21 June, 20:09
How to solve x^4+4x-1=0? ... ?
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Braxton West
21 June, 20:27
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Using the Quadratic formula
x^4 = (x^2) ^2
hence
(x^2) ^2 + 4x + (-1) = 0
ax^2=1 (x^2) ^2
bx = 4 (x)
c = (-1)
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