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21 June, 20:09

How to solve x^4+4x-1=0? ... ?

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  1. 21 June, 20:27
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    Using the Quadratic formula

    x^4 = (x^2) ^2

    hence

    (x^2) ^2 + 4x + (-1) = 0

    ax^2=1 (x^2) ^2

    bx = 4 (x)

    c = (-1)
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